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The lowest-energy line is due to a transition from the n = 2 to n = 1 orbit because they are the closest in energy. \[ \dfrac{1}{\lambda }=-\Re \left ( \dfrac{1}{n_{2}^{2}} - \dfrac{1}{n_{1}^{2}}\right )=1.097\times m^{-1}\left ( \dfrac{1}{1}-\dfrac{1}{4} \right )=8.228 \times 10^{6}\; m^{-1} \nonumber \]
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Since the value of l depends on the value of n, only certain types of orbitals are possible for each n, as follows (only the highest energy level is shown for each row of elements): FIRST ROW ELEMENTS: n = 1 l = 0 only s orbitals are possible, denoted as 1s orbitals. SECOND ROW ELEMENTS: n =2 l = 0 s orbitals are possible, denoted as 2s orbitals.
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